M20 grade => 1 : 1.5 : 3 => 1 + 1.5 + 3 = 5.5 ______________(i)
=>Cement: Sand: Aggrigate
Dry Volume of Concrete = Wet Volume X 1.54 to 1.57 times volume of concrete
यहाँ पर हम 1.57 मान लेते हैं ,
Now
Cement = ( 1/5.5) X1.57 = 0.285 cum
(in 1 cum conc)
We know that 1 m³ = 1440 kg cement
0.285 m³ = 0.285 X 1440 kg
= 410.4 => 410.4/50 bag = 8 bag (Approx)
Sand = ( 1.5/5.5) X1.57 = 0.428 cum
(in 1 cum conc)
Aggrigate = ( 3/5.5) X1.57 = 0.856 cum
(in 1 cum conc)
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